In other words, the output size is \(n^{2}\) bits, and the problem can be solved by computing APSP.
Is the problem "as hard" as APSP?
Either give a subcubic algorithm for TransitiveClosure, or give a subcubic reduction from APSP or from an equivalent problem to TransitiveClosure.
UnbalancedOrthogonalVectorsHypothesis: Given two sets \(A, B \subseteq \{0, 1\}^d\) such that \(|A| = n\), \(|B| = \sqrt{n}\). There is no algorithm running in time \(O(n^{1.5−\varepsilon} \cdot poly(d))\) (for any \(\varepsilon > 0\)) which decides whether there exist \(a \in A\), \(b \in B\) such that \(a\) and \(b\) are orthogonal.
Prove that UnbalancedOrthogonalVectorsHypothesis is equivalent to the orthogonal vectors hypothesis (OVH).
Given a sequence \(S\) of length \(n\), find the longest subsequence which is a palindrome (that is, a sequence of characters which reads the same backward or forward).
Prove that SETH implies that there is no algorithm for LongestPalindromeSubsequence of runnning time \(O(n^{2−\varepsilon})\).